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'LAYPARK' CORNER [SUDUT TAMBAH KREDIT STAM!!!]
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Originally posted by musang_pulut at 24-2-2007 08:39 PM
Kalau yg ni...
bola 5kg bergrak -10m/s sbb bergerak pada arah bertentangan 
1. M1V1 + M2V2 = (6x12) + (5x-10) = 72kgm/s - 50kgm/s = 22kgm/s
2. (22/11)m/s = 2 m/s
3. Utara
jawapan macam skema SPM |
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Originally posted by windmill at 25-2-2007 05:01 PM
jawapan macam skema SPM
FYI..aku dpt p8 physic masa SPM  |
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Reply #81 windmill's post
akupun xpandai fizik..maka tgk je ah mereka ni menjawab...last blajo fizik masa spm je.....alahai...maths pun ms matrik je.. |
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Reply #79 musang_pulut's post
Ada sikit silap masa aku buat soalan tadi.
Ini pembetulan:
Gerakan satu jasad boleh dihuraikan dengan persamaan V=T |
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[quote]Originally posted by prototaip at 25-2-2007 06:17 PM
Gerakan satu jasad boleh dihuraikan dengan persamaan V=T |
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Reply #86 musang_pulut's post
1.betul
2.betul.
3.aku betulkan jelah....
Giliran kau pula bagi soalan..wahaha |
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Reply #87 prototaip's post
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habis jawapan numb 3 aper? |
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Originally posted by musang_pulut at 25-2-2007 04:05 PM
FYI..aku dpt p8 physic masa SPM
gang2 chemist nih ramai yang pandai physics ker.... |
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Reply #83 juju_amin84's post
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welcome to the group |
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Originally posted by prototaip at 25-2-2007 05:17 PM
Ada sikit silap masa aku buat soalan tadi.
Ini pembetulan:
apalah cikgu nih.. kena potong gaji baru taww :lol |
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aku seronok tengok proto dgn musang_pulut soal jawap physic
maaflah aku tak dapat nak menjawap.. jadi pemerhati jer  |
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Soalan kimia lagi...
Karbaid bertindak balas dengan air membebaskan gas acetylene (sejenis gas mudah terbakar).
1. Kira jumlah isipadu gas acetylene (dlm dm3) yang dibebaskan sekiranya 30.5g karbaid digunakan dalam tindakbalas berkenaan???
2. Bilangan molekul gas acetylene yang dibebaskan
(J.A.R: C=12g/mol, H=1g/mol, Ca=40g/mol, O=16g/mol)
[ Last edited by musang_pulut at 26-2-2007 09:32 AM ] |
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@ musang & proto
xpe..xyah batal..bkn strict sgt..jz to hv fun..
tp nxt time jgn bg jawapn di dlm soalan eh hehehe |
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Reply #94 chemist_UTM's post
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mod nak tanyer, kat cni leh tanyer soalan kim, fiz n maths jer ke?bio xleh? |
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Originally posted by juju_amin84 at 25-2-2007 11:09 PM
mod nak tanyer, kat cni leh tanyer soalan kim, fiz n maths jer ke?bio xleh?
Berikan nama siput sedut...mengikut rank
Kingdom
Phylum
Class
Order
Family
Genus
Species
Subspecies
p/s: tensen aku dgn kajihayat nih:@ |
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Originally posted by musang_pulut at 25-2-2007 10:15 PM
Duk diam2 klu malas
duk diam2 lah nih cikgu |
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Category: Belia & Informasi
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Post time 25-2-2007 04:01 PM
