hubungan antara ketinggian n halaju

dauswq

macam ni ko letak bola atas inclined plane & lepaskan...bola akn jatuh sendiri halaju dikira dari situ

saden

Prinsip Energy Conservation aje jawapannya.

Lagi tinggi incline, lagi tinggi potential energy. Bila lepaskan, sampai bawah PE ni converted into Kinetic Energy. Bila lagi tinggi PE tadi, lagi tinggilah pulak KE (dan velocity) yg telah diconvertkan tu.

Betul ke itu persoalannya? Atau ada benda lain yg tak faham tu?

dauswq

bleh gune conservation energy...betul tu

super_nova

pecutan graviti berdasarkan ketinggian kan...

emiliahani

hehehheheh....dah abis klas...luckily ...derang tak tye...hehe

emiliahani

yeker..........

Originally posted by super_nova at 3-3-2009 06:40 PM
pecutan graviti berdasarkan ketinggian kan...

emiliahani

ni la experimennye......

Originally posted by dauswq at 3-3-2009 04:44 PM
macam ni ko letak bola atas inclined plane & lepaskan...bola akn jatuh sendiri halaju dikira dari situ

emiliahani

ape rumusnye ek...leh bu,tikan

Originally posted by saden at 3-3-2009 05:07 PM
Prinsip Energy Conservation aje jawapannya.

Lagi tinggi incline, lagi tinggi potential energy. Bila lepaskan, sampai bawah PE ni converted into Kinetic Energy. Bila lagi tinggi PE tadi, lagi t ...

super_nova

0.5mv2 ker?? bergantung pada ketinggian dan jisim..rasenyer ler

mbhcsf

oh yes ..that equation yg  ? = 1/2? mgh

super_nova

tenaga keupayaan ngan kinetik??

animaniac

ingat ingat lupa ..

Based on theory of energy conservation


Kinetic Energy = Potential Energy
1/2mv^2 = mgh
1/2v^2 = gh
v^2 = (2gh)
v = sqrt (2gh)
   = sqrt (19.62h)

h = 1 , 2 , 3 , 4 ,5
v =  4.43 ,6.26, 7.67 ,8.86,9.90

base on above result, when h increase v will also increase

* kalau salah betulkan sbb dah lama graduate, so ingat2 lupa la

aku_EnSeM

Originally posted by animaniac at 4-3-2009 03:14 PM
ingat ingat lupa ..

Based on theory of energy conservation


Kinetic Energy = Potential Energy
1/2mv^2 = mgh
1/2v^2 = gh
v^2 = (2gh)
v = sqrt (2gh)
   = sqrt (19.62h)

h = 1 , 2 , 3  ...

Nice, with the assumption that the ball is static relative to the ground initially.

[ Last edited by  aku_EnSeM at 5-3-2009 18:38 ]