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Author: dauswq

Kuiz Matematik Mingguan 30 Apr - 15 Mei

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Post time 8-5-2010 08:15 PM | Show all posts
aiyok 2 org je participate... jap lg aku pun nk try jwb gak
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Post time 8-5-2010 11:47 PM | Show all posts
me dpt solve soklan 1 a je.. soklan laen x reti.. siyes da xingat..
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 Author| Post time 9-5-2010 01:24 AM | Show all posts
me dpt solve soklan 1 a je..  soklan laen x reti.. siyes da xingat..
nickynisa Post at 8-5-2010 23:47


dh dpt try kat snih
ai akn bg kredit extra sbg usaha menjawab
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Post time 10-5-2010 10:01 AM | Show all posts
okies...dlm proses menjawab
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 Author| Post time 10-5-2010 10:03 AM | Show all posts
Post Last Edit by dauswq at 10-5-2010 10:04

cepat2 jwb
assigment MKST due date May 15, 2010
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Post time 10-5-2010 01:36 PM | Show all posts
mana aku nak carik buku2 math neh
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Post time 10-5-2010 03:53 PM | Show all posts
Post Last Edit by isskandar at 10-5-2010 15:55

Soalan 1 a



Soalan 1 c

i.




ii.

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 Author| Post time 10-5-2010 04:09 PM | Show all posts
Reply 27# isskandar

semua jawapan adalah tepat & jitutahniah




soalan lain pula...
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 Author| Post time 10-5-2010 04:11 PM | Show all posts
aku leh check jwpn korang esok....

@jie
cpt jwb..nnt iss kejar
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Post time 10-5-2010 10:33 PM | Show all posts
Soalan 2 a

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 Author| Post time 11-5-2010 03:16 AM | Show all posts
Reply 30# isskandar

belum betul
try lagi

hint: lemparkan bentuk 3 dadu yang dilontarkan secara serentak
cth: bentuk 1st, (2 titik), bentuk 2nd, (3 titik) & bentuk 3rd( titik) = jumlahkn ketiga2 dadu dpt 5 ke tak

then tgk berapa kite boleh dpt 5 dr penjumlahan tersebut
you got it right for the probability of each part
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Post time 11-5-2010 09:35 PM | Show all posts
jap2.. tak paham.. ade dadu yg xde titik ker?? atau apa? tak paham hint uols
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 Author| Post time 12-5-2010 12:12 AM | Show all posts
jap2.. tak paham.. ade dadu yg xde titik ker?? atau apa? tak paham hint uols
isskandar Post at 11-5-2010 21:35


u buat tu dh ok...
tp susunan dadu perlu diambil kira
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Post time 12-5-2010 01:06 AM | Show all posts
Post Last Edit by isskandar at 12-5-2010 01:08

ok dah paham... maknanya

1a + 1b + 3c  = 5
1a + 3b  + 1c = 5
3a + 1b + 1c = 5

1a + 2b + 2c = 5
2a + 1b + 2c = 5
2a + 2b + 1c = 5

maka total probability = (1/216) x 6 = 1/36

betul x?
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 Author| Post time 12-5-2010 11:47 AM | Show all posts
Reply 34# isskandar


    betul
tp belum mnjwb  soalan
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Post time 12-5-2010 01:47 PM | Show all posts
pembetulan soalan 2a

1a + 1b + 3c  = 5
1a + 3b  + 1c = 5
3a + 1b + 1c = 5

1a + 2b + 2c = 5
2a + 1b + 2c = 5
2a + 2b + 1c = 5

maka total probability = (1/216) x 6 = 1/36
peratusan mendapatkan jumlah 5 = (1/36) x 100 = 2.778%
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 Author| Post time 12-5-2010 02:18 PM | Show all posts
pembetulan soalan 2a

1a + 1b + 3c  = 5
1a + 3b  + 1c = 5
3a + 1b + 1c = 5

1a + 2b + 2c = 5
...
isskandar Post at 12-5-2010 13:47


nanti dpt tacang ya...
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Post time 15-5-2010 02:59 AM | Show all posts




saya x pasti ni ker bentuk jawapan yang kamu nak.
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 Author| Post time 15-5-2010 03:50 AM | Show all posts
saya x pasti ni ker bentuk jawapan yang kamu nak.
TaufiqTea Post at 15-5-2010 02:59


good try..u still get the credits for your works

tapi ai nak trigonometri expansion for cos 5x using De Moive
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Post time 15-5-2010 10:21 PM | Show all posts
aku leh check jwpn korang esok....

@jie
cpt jwb..nnt iss kejar

dauswq Post at 10-5-2010 16:11


daus laling....

kuizz kali jie surrender dowh...


cuti sem..otak pon cuti ler.. 
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